4n^3-15n+2/n-3

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Solution for 4n^3-15n+2/n-3 equation:


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

4*n^3-(15*n)+2/n-3 = 0

4*n^3-15*n+2/n-3 = 0

4*n^3-15*n^1+2*n^-1-3*n^0 = 0

(4*n^4-15*n^2-3*n^1+2*n^0)/(n^1) = 0 // * n^2

n^1*(4*n^4-15*n^2-3*n^1+2*n^0) = 0

n^1

4*n^4-15*n^2-3*n+2 = 0

{ 1, -1, 2, -2 }

1

n = 1

4*n^4-15*n^2-3*n+2 = -12

1

-1

n = -1

4*n^4-15*n^2-3*n+2 = -6

-1

2

n = 2

4*n^4-15*n^2-3*n+2 = 0

2

n-2

4*n^3+8*n^2+n-1

4*n^4-15*n^2-3*n+2

n-2

8*n^3-4*n^4

8*n^3-15*n^2-3*n+2

16*n^2-8*n^3

n^2-3*n+2

2*n-n^2

2-n

n-2

0

4*n^3+8*n^2+n-1 = 0

{ 1, -1 }

1

n = 1

4*n^3+8*n^2+n-1 = 12

1

-1

n = -1

4*n^3+8*n^2+n-1 = 2

-1

{ 1/2, -1/2, 1/4, -1/4, -1/2, 1/2, -1/4, 1/4 }

1/2

n

1/2

4*n^3+8*n^2+n-1 = 2

1/2

-1/2

n

-1/2

4*n^3+8*n^2+n-1 = 0

-1/2

n+1/2

4*n^2+6*n-2

4*n^3+8*n^2+n-1

n+1/2

-4*n^3-2*n^2

6*n^2+n-1

-6*n^2-3*n

-2*n-1

2*n+1

0

4*n^2+6*n-2 = 0

DELTA = 6^2-(-2*4*4)

DELTA = 68

DELTA > 0

n = (68^(1/2)-6)/(2*4) or n = (-68^(1/2)-6)/(2*4)

n = (2*17^(1/2)-6)/8 or n = (-2*17^(1/2)-6)/8

n in { (-2*17^(1/2)-6)/8, (2*17^(1/2)-6)/8, 2, -1/2}

n in { (-2*17^(1/2)-6)/8, (2*17^(1/2)-6)/8, 2, -1/2 }

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